Re: Possible base-20 numeric system

Trebor Jung wrote:

> Compounds:
>
> ketïs: twenty
> koltïs: thirty
> neltïs: forty
> ötïs: fifty
> sabtïs: sixty
> haudïs: seventy
> mbitïs: eighty
> naetïs: ninety
> tistïs: one hundred
> üstistïs: one hundred and one
> rastïs: one hundred and ten
> üsrastïs: one hundred and eleven
> töltïs: one hundred and twenty
> ðaertïs: one hundred and thirty
> ...
> ketïstïs: two hundred
> ...
> tistïstïs: two hundred
> ...
No, wrong, you have a bizarre dual-base system.  Each of the quoted
should be 20 more than its predecessor.  In the next "place", each would
be 20*20=400 more than its predecessor.
Also, you must (well, should) only have one name for each integer, but
you have:
ketïs-tis = koltïs (assuming hyphens add the two numbers)

A better scheme:
nol = ^0 ... köt = ^19

I will epress the base-20 numbers in ways such as this:
7_2_8_1_2
then we have:
nol = _0 = 0
üs = _1 = 1
ket = _2 = 2
kol = _3 = 3
...
eiv = _17 = 17
aum = _18 = 18
köt = _19 = 19

Then things slightly more complicated:
üstïs = _1_0
   = 1*20
   + 0
   = 20

ketïs = _2_0
   = 2*20
   + 0
   = 40

koltïs = _3_0
   = 3*20
   + 0
   = 60

. . .

eivtïs = _17_0
   = 17*20
   + 0
   = 340

aumtïs = _18_0
   = 18*20
   + 0
   = 360

köttïs = _19_0
   = 19*20
   + 0
   = 380

üstïstïs = _1_0_0
   = 1*20*20
   + 0*20
   + 0
   = 400

üstïstïstïs = _1_0_0_0
   = 1*20*20*20
   + 0*20*20
   + 0*20
   + 0
   = 8000

üstïstïstïstïs = _1_0_0_0_0
   = 1*20*20*20*20
   + 0*20*20*20
   + 0*20*20
   + 0*20
   + 0
   = 160000

for complicated numbers:
köttïstïstïs-naetïstïs-ðahtïs-nel
   = _19_9_16_4 = _19_0_0_0 + _9_0_0 + _16_0 + _4
   = 19*20*20*20
   + 9*20*20
   + 16*20
   + 4
   = 155924
--
Simon Richard Clarkstone
s.r.cl*rkst*n*@durham.ac.uk / s*m*n_cl*rkst*n*@hotmail.com

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