Re: Programming a calendar system

Joe scripsit:

> >Exactly how you compute this depends on the language.  In many C-like
> >languages the type of the result of the '/' operator depends on the type
> >of its operands, so 3296 / 60 = 54, but 3296.0 / 60.0 = 56.933333333
> >etc.  In others the result of / is a float whenever the quotient is not
> >exact, and you have to explicitly apply a function (usually "floor")
> >to get integer form.
>
> Though not, of course, in C itself, which simply gives the answer as an
> integer sans remainder.
Sort of.  In C, i/j is the quotient rounded toward zero (truncated), and
i%j is the remainder, except that it always has the same sign as i.  So
((i/j) * j + i%j) == i is not an identity in C, because:

	((10/-3) * -3) + 10%-3) ==
	(-3 * -3) + 1 ==
	-9 + 1 == -8 instead of -10.

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