Re: The biggest number you know in your conlang
From: | Yahya Abdal-Aziz <yahya@...> |
Date: | Friday, September 22, 2006, 17:53 |
On Fri, 22 Sep 2006, Remi Villatel wrote:
...
> I was looking through my conlang files. I found a file I was absolutely sure
> that I had lost or destroyed it. It was about the very large numbers. So I
> retrieved the largest shaquean number. As far as I know, it's /xotji-gēç/
> [Zo.tji:gEC], or in other words 12^(12^12). You write it as 1 followed by
> over 9800 billions zeroes (in base 12). As far as you know, what is the
> largest numbers in your conlang?
---
Hi Remi,
Uiama counts in sixes; large numbers are powers of the group "latasa" = fourth power
of 6. Selected numbers below (words in parentheses are understood):
---
sa = 1
pa = 2
ka = 3
la = 4
xa = 5
tasa = 6 (times) 1 = 6
tasa sa = 6 (times) 1 (plus) 1 = 7
tasa pa = 6 (times) 1 (plus) 2 = 8
...
tasa xa = 6 (times) 1 (plus) 5 = 11
tapa = 6 (times) 2 = 12
tapa sa = 6 (times) 2 (plus) 1 = 13
...
taxa xa = 6 (times) 5 (plus) 5 = 35
tatasa = 6 (times) 6 (times) 1 = 6^2 = 36
tatasa sa = 6 (times) 6 (times) 1 (plus) 1 = 37
...
tataxa taxa xa = 6 (times) 6 (times) 5 (plus) 6 (times) 5 (plus) 5 = 215
tatatasa = 6 (times) 6 (times) 6 (times) 1 = 6^3 = 216
tatatasa sa = 6 (times) 6 (times) 6 (times) 1 (plus) 1 = 217
...
tatataxa tataxa taxa xa = 6 (times) 6 (times) 6 (times) 5 (plus) 6 (times) 6 (times) 5
(plus) 6 (times) 5 (plus) 5 = 1,295
latasa = 4 (factors of) 6 (times) 1 = 6^4 = 1,296
...
latapa = 4 (factors of) 6 (times) 2 = 6^4x2 = 2,592
...
lataxa tatataxa tataxa taxa xa = 6 (times) 6 (times) 6 (times) 6 (times) 5 (plus) 6
(times) 6 (times) 6 (times) 5 (plus) 6 (times) 6 (times) 5 (plus) 6 (times) 5
(plus) 5 = 1,296^6 - 1
tasa latasa = 6 (factors) of 4 (factors of) 6 (times) 1 = (6^4)^6 = 1,296^6
...
latasa latasa = 1,296 (factors of) 1,296 = 1,296^1,296
...
latasa latasa latasa = 1,296 (factors of) 1,296 (factors of) 1,296 = 1,296^1,296^1,296
---
This is the largest number commonly used, but mostly in expressions, since the
Uiama Makpo have little everyday use for numbers which dwarf the googolplex (a
mere 10^10^100). However, their cosmology produces very different estimates of
the number of entities in their universe than our modern physics does here, for
which a googolplex certainly suffices.
Interesting timing: I was just in the throes of writing up the larger numbers of Uiama
when your question arrived. The documentation is still not complete; for
example, additional particles ensure precision in conveying exact numbers where
necessary, connecting digits by:
i = with
ki = similar; multiply
ro = grow, power of, exponentiate
and so on. And fractions will be fun; everyday terms use the convenient
divisibility of 6 by 2 and 3, and of 6^4 by 2, 3, 4, 6, 8, 9, 12, 15, 16, ...
648, whilst technical uses mirror the structure of the positive integers, but
using negative exponents.
Regards,
Yahya
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