Theiling Online    Sitemap    Conlang Mailing List HQ   

Re: CHAT: math

From:Lars Henrik Mathiesen <thorinn@...>
Date:Monday, November 20, 2000, 20:16
> Date: Sat, 18 Nov 2000 18:04:35 -0500 > From: "H. S. Teoh" <hsteoh@...>
> On Sat, Nov 18, 2000 at 06:56:32PM -0500, John Cowan wrote: > OK, for the record, let me clarify what I was trying to say: > > Let f be a function that has polynomial magnitude p. (I'll skip the > definition unless you really want me to clutter this list with it -- for > now, it suffices to say that the power function x^p is one possibility for > f.) Let g(x) = f(x)*log(x), where log(x) is the natural logarithm. The > magnitude of g is therefore (p+lambda). (Again I omit a very lengthy > definition.) > > Then, for *every* function g that has polynomial magnitude q > p, it holds > that: > p < p+lambda < q > > (p+lambda) is only one among a whole hierarchy of "infinitesimal" > magnitudes. Let n*lambda denote the magnitude of h(x) = (log^n)(x), where > log^n is the natural logarithm composed with itself n times. Then, for > all functions g with polynomial magnitude q, > p < p + n*lambda < q > > Now, let L(x) be the iterated logarithm of x. Let l denote the magnitude > of L. Then: > p < p + l < p + n*lambda < q > for all n>=1. Hence, l behaves like an infinitesimal of infinitesimals. > (I haven't actually proven this last assertion yet, but I've strong > evidence that this is true.)
Are you trying to characterize the asymptotic behaviour at infinity of any real (positive) funtion? What magnitude do you get for e^\sqrt{log x log log x} ? Or the inverse Ackermann function? Lars Mathiesen (U of Copenhagen CS Dep) <thorinn@...> (Humour NOT marked)