Re: Phono

--- Robert Hailman <robert@...> wrote:

> However, if I define "i" as being [=long], then if I
> ever come across a
> long /i/, the program won't use "i" to represent it.
> If you don't have a
> letter defined to represent long /i/, it'll probably
> show a question
> mark in it's place.
    Just to make sure I understand it:

    So, if at some point /t/ differentiates into
aspirated and unaspirated, then I would have /t/ as
[=asp] and /th/ as /T/[#asp]. Then when the output
phase hits, /th/ must become /T/, because it is always
aspirated. Working backwards, if the two merged, with
/T/ > /t/, then I would mark them both with single
features (+,-), and /T/ would show up highlighted,
with a [+asp] feature elaboration.

    Do I have it right?

    Thanks a bunch. This explanation made more sense
(if I got it right, it made a LOT more sense!).

    Aidan


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