Re: OT: CONCULTURE: Ayeri calendar again
| From: | Carsten Becker <naranoieati@...> |
|---|
| Date: | Sunday, January 16, 2005, 15:48 |
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Hello!
OK, here comes the moon-based calendar for my Ayeri people.
I dumped some of the bits I posted recently and made it
completely based on the two moons. As there are two moons
and the sun year may also be involved (though not necessary
actually), dates will still get quite long.
The calendar is supposed to begin on June 22, 402 BC at
11:16:36 GMT. You need the exact time for being able to
tell which time it is right NOW. The calendar is called
"Curan Tertanyan" after its inventor, Tertanyan.
There are still the two moons COLUN and VICAMA, whose "year"
cycles are 324 (cyear) and 608 days (vyear). One cmonth has
24 days, one vmonth has 64 days. Thus, there are 13.5
cmonths per cyear and 9.5 vmonths per vyear. Because people
use 14 cmonths/cyear and 10 vmonths/vyear, in both
calendars every two years there is one month less. The day
is only devided into three parts, Morning, Afternoon and
Night.
Now for the Maths, this is where I got stuck as usual. Since
I don't trust my computer and my programming skills anymore
(it told me the UNIX epoch would be at c0000/c01/c00 at 0
hrs in the end), so I'm going to do everything by hand and
prove it with the computer and my calculator to see what I
did wrong last time. It's also easier for you to point out
errors then.
For implementing this on the computer, we need to know how
much time passed until the UNIX epoch started on 1/1/1970
00:00:00 GMT. To make the conversion easier, things are
converted into the Julian Date:
01/01/1970 AD 00:00:00 => 2440587.50000 edays
- 22/06/ 402 BC 11:16:36 => 1574764.96986 edays
1111 1 1111
-----------------------------------------------
Time passed: 865822.53014 edays
==================
Since the smallest given unit is the hour, according to Mark
Reed's explanations, we now have to multiply the result
with 24 because there are 24 hours in a day on earth:
865822.53014 x 24
111 1
223 12 1 1
-----------------
17316450.60280
+ 3463290.12056
1 1 1
-----------------
20779740.72336 ehrs
==============
However, 1 asec ^= 1.2 esecs, and this gets me confused.
What about hours?! By multiplying the units up to an hour
later, you'll receive values that are 1.2x smaller than the
values for earth if I can trust my knowledge of maths. So
we can divide the result by 1.2 here, too:
207797407.2336 : 12 = 17316450.6028 ahrs
12 =============
--
87 60
84 60
-- --
37 07
36 0
-- --
19 72
12 72
-- --
77 03
72 0
-- --
54 33
48 24
-- --
60 96
96
--
0
In the case the figures aren't right, the method is at
least.
Now our question is how many adays are this? I said, one day
has 3 "hours", so ...
17316450.6028 : 3 = 5772150.20093333... adays
15 ===================
-- 00
23 0
21 --
-- 06
21 06
21 --
-- 00
06 0
6 --
-- 02
04 0
3 --
-- 28
15 27
15 --
-- 10
00 9
--
1
...
This is 5,772,150 adays and 0.6028 ahrs. My computer says
0.60280000045896 ahrs, but anyway.
Now we need to split things into COLUN and VICAMA.
COLUN
=====
According to Mark Reed, we must eliminate the leap years
now: cyear 1 has 336 days while cyear 2 only has 312 days.
I know the calendars get out-of-synch with the moon every
year pretty soon that way, but I'm too biased by our
calendar :P
336 324 x 2
+ 312 -------
===== 648
648
So there you go. One c-"diard" has 648 adays. 5,772,150
adays equal thus ...
5772150 : 648 = 8907 cdiards and 414 cdays.
How many years are 8907 cdiards?
8907 x 2 = 17814 cyears
Now we want to know how many years and days the rest is:
414 : 324 = 1 cyear 90 cdays
This means, the UNIX epoch occured at 17,815 cyears, 90
cdays and 0.6028 ahrs (at late morning).
Since all the cmonths have 24 adays, the month is as
follows:
90 - 24 = 66 => 17815-02-66
66 - 24 = 42 => 17815-03-42
42 - 24 = 18 => 17815-04-18
===========
Thus, the UNIX epoch began on cIV c18, c17815 at late
morning.
VICAMA
======
I don't write all the explanations since it should be clear
now what I'm doing:
608 x 2
1
-------
1216 adays = 1 vdiard
5772150 : 1216 = 4746 vdiards and 1014 vdays
4746 x 2 = 9492 vyears
1014 : 608 = 1 vyear 406 vdays
The UNIX epoch occured at 9,493 vyears, 406 vdays.
All vmonths have 64 days, so ...
406 - 64 = 342 => 9493-02-342
342 - 64 = 278 => 9493-03-278
278 - 64 = 214 => 9493-04-214
214 - 64 = 150 => 9493-05-150
150 - 64 = 86 => 9493-06-86
86 - 64 = 22 => 9493-07-22
===========
The UNIX epoch began on vVII v22, v9493 at late morning.
Since both moons have a conjunction each 49,248 adays, which
would be the equivalent to a century:
49,248 : 324 = 152 cyears
49,248 : 608 = 81 vyears
17,815 : 152 = 117 ccenturies and 31 cyears
9,493 : 81 = 117 vcenturies and 16 vyears
All in all, the UNIX count began on 117-117-31-16-4-7-18-22
at late morning. I only wonder if the two numbers for the
centuries keep always the same. In base-12 which is
normally used, this would of course be
99-99-27-14-4-7-16-1A.
More to follow. I'm going to see if I can program this with
PHP so that you can enter any date you like and the
computer spits out the other date.
It's been a jungle, but I hope you liked it.
Carsten
--
Eri silveváng aibannama padangin.
Nivaie evaenain eri ming silvoieváng caparei.
-- Antoine de Saint-Exupéry, Le Petit Prince
http://www.beckerscarsten.de/?conlang=ayeri